A balloon is left in the sun and heats up from 29.4°C to 33.7%. If the balloon was originally at 0.68L, what is the new volume of the balloon?

0.78L

Explanation:

According to Charles law, the equation below can be used to calculate the the new volume of the balloon

V1/T1 = V2/T2 eqn(1)

Where T1= initial temperature= 29.4°C

T,2= final temperature= 33.7°C

V2= final volume= ?

V1= initial volume= 0.68L

Making V2 the subject of formula from eqn(1)

V2=( T2 × V1)/T1

= (33.7 × 0.68)/29.4

=0.78L

Hence, the new volume of the balloon is 0.78L

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.