What volume (mL) of 0.250 M HNO3 is required to titrate (neutralize) a solution containing 0.276 g of KOH?

Volume = 19.68 ml

Explanation:

The equation of the reaction is given as;

HNO3 + KOH ---> KNO3 + H2O

1 mol of HNO3 reacts 1 mol of KOH

Converting 0.276 g of KOH to mol;

Number of moles = Mass / Molar mass

Number of moles = 0.276g / 56.1056 g/mol

Number of moles = 0.00492

Since the mole relationship is 1 = 1;

This means 0.00492 mol of HNO3 reacts with 0.00492 mol of KOH

The relationship between molarity and volume id given as;

Molarity = Number of moles / Volume

Volume = Number of moles / Molarity = 0.00492 mol / 0.250 M

Volume = 0.01968 L

Volume = 19.68 ml

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e