When benzene is treated with 2-methylpropene and sulfuric acid, the product obtained is tert-butylbenzene. Propose a mechanism for this transformation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer.

See explanation and image attached

Explanation:

This reaction begins when the pi bond in 2-methylpropene is attacked by a proton. A tertiary carbocation is formed which now may attack a benzene ring in an electrophilic reaction. A tertiary carbocation is very stable.

The electrophilic attack of the tertiary carbocation yields the final product  tert-butylbenzene as shown in the image attached.

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.

The correct answer should be "electrons orbit the nucleus in circular motions exactly as shown on the classic bohr model."