What is the mole percent of ethanol (C2H5OH), which consists of 71.0 g of ethanol for every 18.6 g of water present?A. 87.7%.B. 22.1%.C. 26.5%.D. 73.5%.E. 71.0%.

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

Explanation:

Mole percent is the percentage of the total moles that is of a particular component.

We have to covert the ethanol and water to moles. This is given by the equation;

Number of moles =  Mass / Molar mass

Ethanol;

Number of moles = 71 / 46.07  = 1.5411 mol

Water;

Number of moles = 18.6 / 18  = 1.033 mol

Total mol = 1.5411 mol + 1.033 mol =  2.5741 mol

Mole percent of Ethanol = Number of moles /(Ethanol) / Total moles   * 100

Mole percent of Ethanol =  1.5411 mol / 2.5741 mol   * 100

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

2b2t

explanation:

2b2t

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be