A 200.0 g sample of metal at a temperature of 120.0°C is placed into a container of water. There are 300.0 grams of water (CH20=4.18j/g°C) in the container at a temperature of 30.0°C, the final temperature of the water is 36.0°C. What is the specific heat of the metal?

Idon’t know how to solve this question

Acalorimeter is to be calibrated: 51.203 g of water at 55.2 degree c is added to a calorimeter containing 49.783 g of water at 23.5c. after stirring and waiting for the system to equilibrate, the final temperature reached is 37.6 degree c. specific heat capacity of water (s = 4.18 j/g∙degree c). calculate the calorimeter constant. (smδt)warm water = -[(smδt)cold water + (calorimeterδtcold water)]

Pls ill give u brainliest which of the following is true about science? 1. political conditions are unable to influence it. 2. economic concerns may prevent it from solving problems.