This equation represents cellular respiration. C6H12O6 +602
6 CO2 + 6H2O + energy
Which table lists all the atoms in reactants and products of cellular respiration?
Reactants 6 C 12 H 18 O
ΟΑ.
Products 6 C 12 H 18 O
Reactants 6 C 6H 2
Ов.
Products 6 C 12 H 120
Reactants 6 C 12 H 120
C.
Products 6 C 12 H 30
Reactants 6 C 12 H 18 0
D.
Products 1C6H 18 O

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

if you're asking what comes out, it's steam.

it has both hydrogen and oxygen