What is the net ionic equation for the following reaction? Rb2CrO4(aq) + 2AgClO(aq) --> 2RbClO(aq) + Ag2CrO4(s)

Group of answer choices

Rb+(aq) + ClO-(aq) --> RbClO (s)

2Rb+(aq) + CrO42+(aq) --> Rb2CrO4 (s)

Ag+(aq) + ClO-(aq) --> AgClO (s)

2Ag+(aq) + CrO42+(aq) --> Ag2CrO4 (s)

The net ionic equation  is

Ag⁺(aq)  +Cl⁻(aq) →  AgCl(s)

Explanation:

AgNO₃ (aq)  + KCl (aq)→ AgCl(s) +KNO₃(aq)

from above  molecular equation break  all  soluble electrolyte  into ions

Ag⁺(aq) +NO₃⁻ (aq) + K⁺(aq) +Cl⁻(aq) →   AgCl (s) + K⁺(aq) + No₃⁻(aq)

cancel the spectator  ions  in both side  of  equation =K⁺  and NO₃⁻  ions

The net  ionic equation is therefore

= Ag⁺(aq)  + Cl⁻(aq) →    AgCl(s)

43.452

step-by-step explanation:

284 times .153 = 43.452

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer