Fe2o3+2al=al2o3+2fe
a welder has 1.873 _ 10^2 g fe2o3 and 94.51 g al in his welding kit. which reactant will he run out of first? (options: fe2o3 or 's fe2o3).
how much of this reactant should he order to make sure he runs out of both reactants at the same time?
he should order of the limiting reactant.

92.41g, this is the correct answer

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"