What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic weight of Ca is 40.1 and the atomic weight of Br is 79.9.
A) 452.3 g
B) 53.04 g
C) 44.2 g
D) 88.4 g

Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9  

To calculate the moles, we use the equation:

Thus there are 88.4 g of calcium bromide.