Use coulomb's law to calculate the ionization energy in kj/mol of an atom composed of a proton and an electron separated by 185.00 pm .

Energy = 752.88 kJ/mol

Explanation:

The force of attraction can be written as:

Integrating to find the expression for energy. We get that:-

Where,  

K is the Coulomb's constant having value 9×10⁹ N. m²/C²

 is the charge on the cation

 is the charge on the anion

e is electronic charge = Charge of the electron = Charge on proton

r is the distance between the cation and anion  = 185.00 pm

Also, 1 pm = 10⁻¹² m

So, r = 185×10⁻¹² m

Applying in the equation,  

Also,

1 atom =

So,

Energy =

Also, 1 J = 0.001 kJ

So, Energy = 752.88 kJ/mol

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer