A student tried to solve the following problem by selecting the conversion below. What, if anything, did the student do wrong? (I suggest you try to complete the problem yourself, then select the correct answer).

How many moles of AgNO3 are needed to produce 6.75 moles of copper (II) nitrate Cu(NO3)2 upon reacting with excess copper (Cu)?

2AgNO3 + Cu --> 2Ag + Cu(NO3)2

Students conversion factor: 6.75 mol Cu(NO3)2 x 1 mol Cu(NO3)2/2 mol AgNO3
Question 1 options:

The student chose the wrong conversion factor.

The student chose the correct conversion factor, but need to flip it to make units cancel.

The student chose the correct conversion factor, but needs to add a second to finish the problem.

There is nothing wrong the problem is ready to be solved.

Read these sentences from the text. near the equator, the tropics receive the most rain on a consistent basis. as a result, the fresh water falling into the ocean decrease the salinity of the surface water in that region. [. .] . . as the salt content of sea water increases, so does its density. what can you infer about how rain affects the density of surface water near the equator?

Several kinds of bears are found on earth. most bears are brown or black, but one type of bear, the polar bear, is white. what process led to this difference in fur color? explain your answer.

Oxidation-reduction reactions (often called "redox" for short) are reactions that involve the transfer of electrons from one species to another. oxidation states, or oxidation numbers, allow chemists to keep track of these electron transfers. in general, one element will lose electrons (oxidation), with the result that it will increase in oxidation number, and another element will gain electrons (reduction), thereby decreasing in oxidation number. the species that is oxidized is called the reducing agent or reductant. the species that is reduced is called the oxidizing agent or oxidant. to sum up: oxidation = increase in oxidation state = loss of electrons = reducing agent reduction = decrease in oxidation state = gain of electrons = oxidizing agent part a which element is oxidized in this reaction? fe2o3+3co→2fe+3co2 enter the elemental symbol. view available hint(s) is oxidized part b which element is reduced in this reaction? 2hcl+2kmno4+3h2c2o4→6co2+2mno2+2kcl+4h2o enter the elemental symbol. view available hint(s) is reduced