How many moles of oxygen are required to completely burn 1.25 moles of Carbon Dioxide? 2C4H10 + 1302 → 8 CO2 + 10H20
0.77
2.03
1.61
0.55

5 mol CH4 x (2 mol O2/1 mol CH4) = 10 mol O2

Explanation:

Start with a balanced equation.

CH4 + 2O2 → CO2 + 2H2O

You can see from the balanced equation that one mole of CH4 reacts completely with two moles of O2. So five moles of CH4 would require ten moles of O2. However, you can also show this with stoichiometry.

Multiply 5 mol CH4 by the mol ratio between O2 and CH4 in the balanced equation so that mol CH4 cancels, leaving mol O2.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.