According to the reaction below, how many grams of KCl (potassium chloride) can be formed from 106.35 g of chlorine with excess potassium? 2K + Cl2 ---> 2 KCl

225 grams

Explanation:

Given:       K      +     Cl₂        =>     2KCl

             excess    106.35g             ?grams

Suggestion: For stoichiometry problems, convert all data given to moles and solve by ratio based on given equation and relative data given. After working in terms of moles, convert to dimension specified in problem.

moles Cl₂ = 106.35g / 70g/mol = 1.52 moles

From balanced equation:

 1mol Cl₂        => 2mol KCl

  1.52 mol Cl₂ => ?(mol KCl)

∴moles KCl produced = 2 mol KCl x 1.52 mol Cl₂ / 1 mol Cl₂ = 3.04 mol KCl

Grams KCl = 3.04 mole x 74 grams/mole = 225 grams