How many moles of AgNO3 are needed to produce 6.75 moles of copper (II) nitrate Cu(NO3)2 upon reacting with excess copper (Cu)? 2AgNO3 + Cu --> 2Ag + Cu(NO3)2

Students conversion factor: 6.75 mol Cu(NO3)2 x 1 mol Cu(NO3)2/2 mol AgNO3
Question 1 options:

The student chose the wrong conversion factor.

The student chose the correct conversion factor, but need to flip it to make units cancel.

The student chose the correct conversion factor, but needs to add a second to finish the problem.

There is nothing wrong the problem is ready to be solved.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.

answer; 4 electrons;