6 NaOH + 2 AI > 2 Na3AIO3 + 3 H2 How many grams of Na3AIO3 can be formed from 7.24 moles of NaOH?

6NaOH(aq) + 2Al(s) = 2NA3AlO3(s) + 3H2(g) ... 2 moles of Alreact with 6 moles of NaOH. 3.7 moles of Al ‒ x moles of NaOH. = 3.7 ∙ 6. 2.

Explanation:

1. they vary with a higher number because boiling is way hotter than melting

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