La combustión de 2,25 g de un compuesto orgánico que contiene C, H y O, produce 3,3 g de CO2 y 1,35 g de H2O. Si sabemos que en estado gaseoso 2,25 g de dicho compuesto ocupa un volumen de 1,61 litros a 250ºC y 1 atm de presión. Determina: a) Su fórmula empírica. B) Su fórmula molecular. C) Escribe una posible fórmula desarrollada de dicho compuesto y nómbrarlo. Datos: Masas atómicas C = 12 u; H = 1 u; O = 16 u

the answer would be a

b. is the answer hoped i        

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol