In a photoelectron spectroscopy experiment, photons with wavelength 130 nm cause the ejection of 6 s electrons from gold, but photons with wavelength 200 nm do not. A student claims this is because the photons with wavelength 200 nm are lower in energy than photons with wavelength 130 nm . Do you agree or disagree with the student's claim? Justify your answer in terms of the energies of the photons.

See explanation

Explanation:

The energy of a photon refers to the energy carried by each photon. The energy of a photon is inversely related to its wavelength.

This simply means that the longer the wavelength of a photon, the lower the energy of the photon.

200nm is longer than 130nm, therefore, 130nm photon has more energy than 200nm photon.

This explains the fact that photons with wavelength 130 nm cause the ejection of 6 s electrons from gold, but photons with wavelength 200 nm do not.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2