A coffee cup calorimeter contains 100.0mL of 1.50 M Ba(NO3)2 at 25.0 degrees Celsius. A student pours 100.0mL of 1.50 M Na2SO4 at 25 degrees Celsius into the calorimeter. A precipitate forms and the temperature rises to 29.7 degrees Celsius. Assume that no heat was lost to the surroundings, the volumes were additive, the specific heat capacity of the solution was 4.184 j/gal and the density of the solution was 1.00 g/mL. A) this reaction could be represented as a complete ionic or a net ionic equation. Write the balanced chemical equation that should be used in association with the value for this reaction.
B) find the amount of the heat that was last or gained by the solution in the calorimeter.
C) find the heat of reaction
D) is the reaction endothermic or exothermic?

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j