Given a Ksp for AgBr of 5.0 * 10–13, what happens when 50 ml of 0.002 M AgNO3 and 50 mL of 0.002 M NaBr are mixed?

A precipitate will be produced

Explanation:

The Ksp of AgBr is:

AgBr(s) → Ag⁺ + Br⁻

5.0x10⁻¹³ = [Ag⁺] Br⁻]

Where [] are the concentrations in equilibrium of each ion.

And if Q is:

Q = [Ag⁺] Br⁻]

Where the concentrations are actual concentrations of each ion

We can say:

IF Q >= Ksp, a precipitate will be produced

IF Q < Ksp, no precipitate will be produced.

the molar concentrations are:

[AgNO₃] = [Ag⁺] = 0.002M * (50mL / 100mL) = 0.001M

Because 50mL is the volume of the AgNO₃ solution and 100mL the volume of the mixture of both solutions.

[NaBr] = [Br⁻] = 0.002M * (50mL / 100mL) = 0.001M

Q = [0.001M] * [0.001M]

Q = 1x10⁻⁶

As Q > Ksp,

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be