C6H12O6 -> 2C2H5OH + 2CO2Determine the volume of carbon dioxide gas produced when 7.0 moles of glucose decomposes at STP

313.6 L

Explanation:

use mole/mole ratio to find moles of CO2 (=14)

multiply by 22.4

=313.6 L

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

where's the diagram?