An unknown monoprotic acid reacts with NaOH. The acid solution is made by dissolving 6.945 g of the acid in enough water to make 500.0 ml solution. The titrations were carried out on 10.00 ml samples of this acid solution
0.0987 molar NaOH is used to make 4 titations. The volumes of NaOH dispensed are 11.88 ml, 11.93 ml, 11.83 ml and 11. 87 ml. What is the molar mass of the unknown acid. Keep the correct number of significant figures in your answer and show me the work.

c, liquids evaporate, creating a gas

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole