2 moles of sodium phosphate reacts with 3 moles of calcium chloride
2Na3PO4 + 3 CaCl2 -> 6 NaCl + Ca2 (PO4)2
using the chemical equation above, how many moles
of NaCl can be produced if one of these is a limiting
reactant?

6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of  calcium chloride

Explanation:

The balanced chemical equation is:

According to stoichiometry :

2 moles of require 3 moles of

Thus both are limiting reagent as both will limit the formation of product.

As 2 moles of reacts with 3 moles of give = 6 moles of

Thus 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of  calcium chloride

the correct answer is:

a. formation of precipitation