A hydrate of zinc chlorate, Zn(CIO3)2·XH20, contains 21.5% zinc by mass. Find the value of X.

What I've done:

Molar mass of Zn: 65.409 g/mol

Molar mass of Cl: 2*35.453 =70.906 g/mol

Molar mass of O: 6*15.9994 =95.9964 g/mol

Total molar mass of Zn(ClO3)2: 232.3114 g/mol

21% of molar mass = 232.3114 g/mol

100% of mass = 1106.244762 g/mol

Molar mass of H2O: 18.01528 g/mol

232.3114 g/mol + 18.01528 g/mol = 250.32668 g/mol

250.32668 = 1106.244762

1106.244762 g/mol divided by 232.3114 g/mol

x = 4.419

Explanation:

% anything = (g/total mass)*100 = ?

Atomic mass Zn = 65.4 from your post.

molar mass Zn(ClO3)2 from your post = 232.3

molar mass H2O = 18

The 21.5% Zn is (note you used 21%) percent Zn in the hydrate so

%Zn = [(65.4)/(232.3 + x*18)]*100 = 21.5%

Solve for x and I obtained 3.99 which rounds to 4.00. Let me know if you don't understand any part.

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