How many moles of H20 are produced by 4.8 moles of O2?
2H2 +O2 > 2H20

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

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12 moles H

2

O

Explanation:

Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.

As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.

In your case, the balanced chemical equation for this synthesis reaction looks like this

2

H

2(g]

+

O

2(g]

→

2

H

2

O

(l]]

Notice that the reaction requires  

2

moles of hydrogen gas and  

1

mole of oxygen gas to produce  

2

moles of water.

This tells you that the reaction produces twice as many moles of water as you have moles of oxygen gas that take part in the reaction.

You know that your reaction uses  

6.0

moles of oxygen. Assuming that hydrogen gas is not a limiting reagent, you can say that the reaction will produce

6.0

moles O

2

⋅

2

moles H

2

O

1

moles O

2

=

12 moles H

2

O

hope this helps

o(*°▽°*)o

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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