How many grams of CO 2 are present in a container with a volume of 5.61 L if the gas exhibits a pressure of 5.66 atm at a temperature of 311 K?

54.72 g

Explanation:

Mass = ?

Volume = 5.61 L

Pressure = 5.66 atm

Temperature = 311 K

The relationship between these equations is given by the ideal gas equation;

PV = nRT

where R = gas constant = 0.0821 atm L K-1 mol-1

n = PV / RT

n = 5.66 * 5.61 / (0.0821 * 311 )

n = 1.2436 mol

Number of moles = Mass / Molar mass

Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g

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