Select the most likely product for this reaction: Upper K subscript 2 upper C upper O subscript 3 (a q) plus upper C upper O subscript 2 (g) right arrow question mark.
K2CO3(aq) + H2O(l)
K(s) + H2(g) + O2(g)
K(s) + CO3(g) + H2

The answer is A- K2CO3(aq)+H2O(I)

Explanation:

The person who made this question gave the answer so...eh??

A) K2CO3(aq) + H2O(l)

Explanation:

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.