Determine how many moles of water (H2O) are formed from the combustion of 7.50 x 1023 molecules of propane (C3H8). 1 C3H8 (g) + 5 O2 (g) ⟶ 3 CO2 (g) + 4 H2O (g)

4.98 moles of H₂O

Explanation:

The balanced chemical equation for the combustion of propane is:

C₃H₈ (g) + 5 O₂ (g) ⟶ 3 CO₂ (g) + 4 H₂O (g)

That means that 1 mol of propane (C₃H₈) produces 4 moles of water (H₂O).

We know that 1 mol is equal to 6.022 x 10²³ molecules. So, we convert the molecules of propane to moles as follows:

7.50 x 10²³ molecules C₃H₈ x 1 mol/6.022 x 10²³ molecules = 1.245 mol C₃H₈

Now, we use the stoichiometric ratio 4 mol H₂O/1 mol C₃H₈ derived from the chemical equation to calculate the moles of water produced:

1.245 mol C₃H₈ x 4 mol H₂O/1 mol C₃H₈ = 4.98 mol H₂O

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.