Determine the mass of aluminum (Al) produced in the reaction if 30.00 grams of magnesium (Mg) was consumed with the equation given; 2 AlPO4(aq) + 3 Mg(s) = 2 Al(s) + 1 Mg3(PO4)2(aq)

22.21 grams of aluminum (Al) was produced in the reaction if 30.00 grams of magnesium (Mg) was consumed.

Explanation:

The balanced reaction is:

2 AlPO₄ (aq) + 3 Mg (s) → 2 Al (s) + 1 Mg₃(PO₄)₂ (aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Being the molar mass of each compound:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

You can apply the following rule of three: if by stoichiometry 72.93 grams of Mg produces 54 grams of Al, 30 grams of Mg produces how much mass of Al?

mass of Al= 22.21 grams

22.21 grams of aluminum (Al) was produced in the reaction if 30.00 grams of magnesium (Mg) was consumed.

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