Determine the mass of Iron (III) oxide (Fe2O3) produced in the decomposition reaction of 100.0 grams of Iron (III) hydroxide (Fe(OH)3). 2Fe(OH)3(s)-1Fe2O3 (s) +3H2O (g)

77.47 g of will be produced from 100.0 g of Iron (III) hydroxide

Explanation:

To calculate the moles :

The balanced chemical equation is:

According to stoichiometry :

2 moles of produce = 1 mole of

Thus 0.935 moles of will producee=  of

Mass of

Thus 77.47 g of will be produced from 100.0 g of Iron (III) hydroxide