For the reaction C2H2(g) + 3 O2(g) – 2 CO2(g) + 2 H2O(g)
What number of grams of CO2 could be produced from 2.0 g of C2H4 and 5.0 g of O2?

3.3792 g

Explanation:

The balanced equation for the reaction is given as;

2 C2H2(g) + 3 O2(g) --> 2 CO2(g) + 2 H2O(g)

From the reaction;

2 mol of C2H2 requires 3 mol of O2

2.0 g of C2H2

Number of moles = Mass / Molar mass = 2 / 26.04 = 0.07680 mol

5.0 g of O2

Number of moles = Mass / Molar mass = 5 / 32 = 0.15625 mol

The limiting reactant is; C2H2

2 mol of C2H2 produces 2 mol of CO2

0.07680 mol produces x

Solving for x;

x = 0.07680 mol

Mass = Molar mass * Number of moles = 44 g/mol * 0.07680 mol = 3.3792 g

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explanation:

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