2). H2S and SO2 as follows,(8pt) H2S + SO2 >S + H2O

In a particular experiment, 7.95 g of sulfur is produced by the reaction of 7.5 g of H2S with 12.75 g of SO2.

What is the % yield of sulfur?

75.7 % yield

Explanation:

The balanced chemical equation is:

According to stoichiometry :

68.2 g of will require = 64 g of

Thus 7.5 g of will require = of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 68.2 g of give = 96 g of

Thus 7.5 g of give =  of

% yield=

Thus 75.7 % yield is there.