Chemistry, 18.03.2021 02:00 FailingstudentXD
The oxidation and reduction equations for the following reaction are
Pb(s) + Cu2+(aq) → Pb2+(aq) + Cu(s)
I.
Oxidation reaction
Pb (s) > Pb2 + (aq) + 2e Pb is oxidizing agent
Reduction reaction
Cu2 +(aq) + 2e- > Cu (s) Cu2 + is reducing agent
II.
Oxidation reaction
Pb (s) > Pb2 + (aq) + 2e Pb is oxidized
Reduction reaction
Cu2 + (aq) + 2e- > Cu (s) Cu2 + is reduced
III.
Oxidation reaction
Cu2 + (aq) + 2e- > Cu (s)
Reduction reaction
Pb (s) > Pb2 + (aq) + 2e
IV.
Oxidation reaction
Cu (s) + 2e- > Cu2+ (s)
Reduction reaction
Pb2+ (aq) > Pb (s) + 2e
Answers: 2
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The oxidation and reduction equations for the following reaction are
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