A compound was analyzed in a lab to determine its empirical formula. Decomposition of the compound at a standard temperature and pressure produced
9.00g carbon, 16.8L hydrogen, and 2.80L oxygen. The molar mass of the compound
is 116g/mol. What is its molecular formula?
please show work

Explanation:

The answers are 5C, 1N, and 5H. The empirical formula is C5H5N, which has a molar mass of 79.10 g/mol. To find the actual molecular formula, divide 240, the molar mass of the compound, by 79.10 to obtain 3. So the formula is three times the empirical formula, or C15H15N3.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml