If the pressure on a gas decreases from 1480 mm Hg at 478 K to 555 mm Hg, what is the final temperature? V​1​ = P​1​ = T​1​ =
V​2​ =
Law:
P​2​ =
T​2​ =

179 K

Explanation:

From the question given above, the following data were:

Initial pressure (P₁) = 1480 mm Hg

Initial temperature (T₁) = 478 K

Final pressure (P₂) = 555 mm Hg

Final temperature (T₂) =?

The final temperature of the gas can be obtained as follow:

P₁/T₁ = P₂/T₂

1480 / 478 = 555 / T₂

Cross multiply

1480 × T₂ = 478 × 555

1480 × T₂ = 265290

Divide both side by 1480

T₂ = 265290 / 1480

T₂ ≈ 179 K

Therefore, the final temperature of the gas is 179 K

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