How many ml of a 4.0 M Mg(OH)2 are needed to make 750 ml of 0.2 M Mg(OH)2???

37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂

Explanation:

Dilution is the reduction in concentration of a chemical in a solution. Dilution consists of lowering the amount of solute per unit volume of solution.

In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and consists of adding solvent to an existing solution. The quantity or mass of the solute is not changed but only that of the solvent.

In dilutions the expression is used:

Ci*Vi = Cf*Vf

where:

In this case:

Replacing:

4 M* Vi= 0.2 M* 750 mL

Solving:

Vi= 37.5 mL

37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

beta decay is the answer