2KClO3 → 2KCl + 3O2 How many moles of potassium chloride are produced by the decomposition of 9.0 moles of potassium chlorate, KClO3?

9.0

Explanation:

l

mol

Explanation:

Potassium chlorate

KClO

3

decomposes to produce potassium chloride

KCl

and oxygen

O

2

. Balancing the equation

KClO

3

→

KCl

+

O

2

(not balanced)

based on the fact that the number of moles of oxygen atoms should be the same on both side of the equation will give

KClO

3

→

KCl

+

3

2

O

2

2

KClO

3

→

2

KCl

+

3

O

2

Hence the ratio of number of moles of particles

n

(

O

2

)

n

(

KClO

3

)

=

3

2

n

(

O

2

)

=

n

(

KClO

3

)

⋅

n

(

O

2

)

n

(

KClO

3

)

=

3

2

⋅

n

(

KClO

3

)

Therefore the decomposition of

6.0

l

mol

of

KClO

3

would yield

6.0

⋅

n

(

O

2

)

n

(

KClO

3

)

=

6.0

⋅

3

2

=

9.0

l

mol

Note that the species

KCl

is highly stable. Both the potassium cation

K

+

and the chloride anion

Cl

−

have attained a noble gas octet configuration of valence shell electrons. Chemical reactions tend to favor the most chemically stable combination. Therefore this decomposition reaction would eventually produce

KCl

rather than other salts that contain oxygen.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

there is none because earth is stationary and flat.