A mixture contains 21.7 g NaCl, 3.74 g KCl, and 9.76 g Lici.
How many total moles are in this
mixture?
Molar Mass
Naci: 58.44 g/mol
KCI: 74.55 g/mol
Lici: 42.39 g/mol

Explanation is in the file

cutt.ly/nz6VGda

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole