A 24.93 g sample of ice is heated from -16 oC to its melting point of 0 oC and then melted completely. Next it is raised to its boiling point of 100 oC and boiled completely. Finally the sample is heated to 113 oC. How much energy was absorbed by the sample? (Answer in kJ pay close attention to units!) Sice=2.1 J/goC Delta Hf = 6.02 kJ/mol

Ssteam=1.7 J/goC Delta Hv = 2.26 kJ/g

може ли да зареждате повече информация, моля

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2