If some methane gas at 115 kPa and 33C is allowed to expand to 15.0dm^3 from 8.00 dm^3 when the temperature changed to 51.2 C. What pressure will the same amount of gas exert?

228.4 kPa

Explanation:

From thw question,

PV/T = P'V'/T' Equation 1

Where P = Inital pressure, T = Initial Temperature, V = Initial Volume, P' = fInal Pressure, V' = Final volume, T' = Final Temperature.

Make P' the subject of the equation

P' = PVT'/TV' Equation 2

Given: P = 115 kPa, V = 15.0 dm³, T = 33°C = (33+273) K = 306 K, T' = 51.2°C = 51.2+273 = 324.2 K, V' = 8.00 dm³

Substitute these values into equation 2

P' = (115×15×324.2)/(306×8)

P' = 228.4 kPa.

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i