What is the [oh–] in a solution of ph 3.00?
a. 1.0 x 10–9 m
b. 1.0 x 10–6 m
c. 1.0 x 10–3 m
d. 1.0 x 10–11 m
e. 11.00 m

The value of is

Explanation;

The relation of ph and pOh is given as:

pH+pOH=14

pOH = 14 - 3 = 11

The pOH is defined as negative logarithm of hydroxide ion concentration.

The value of is

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72