C3H8(g) + 5 O2(g) >3 CO2 (g)+ 4H2O (g) If the experiment contains 75.0 grams of O2, how many grams of H2O should be produced?

33.75g H2O

Explanation:

75g O2 (1 mol O2/32g O2) (4 mol H2O/5 mol O2) (18g H2O/1 mol H2O) = 33.75g H2O

This is a stoichiometric calculation in which 75 is multiplied by 1, 4, and 18 (the top numbers), and then divided by (32 x 5 x 1), which are the bottom numbers.

Stoichiometry is super fun once you get the hang of it!!

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

l dont know l am s sorry