When 0.8788 g of a liquid isolated from oil of balsam was burned completely, 2.839 g of C02 and 0.9272 g of H20 were obtained. The molecular mass of the compound was found to be 136.2. Calculate the empirical and molecular formulas of this compound.

Wow that a lot of text for my tiny so i no wanna answer

The answer to your q it is d

3-isopentane; 3-methylbutane, and 1,2-methylpropane do not meet iupac rules, so they are wrong names.the only valid name onthe list is 2-methylbutane, which is the same isopentane.this is its formula:                   ch2                    |ch3 - ch - ch2 - ch3answer: 2-methylbutane