A sample of hydrogen gas has an initial temperature of 50° C. When the temperature is lowered to -5° C, the volume of hydrogen becomes 212 cm^3. What was the initial volume of the hydrogen in cm^3 when the pressure is kept constant?

255.51 cm³

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50° C

Final temperature (T₂) = –5° C

Final volume (V₂) = 212 cm³

Initial volume (V₁) =?

Next, we shall convert celsius temperature to Kelvin. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50° C

Initial temperature (T₁) = 50° C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = –5° C

Final temperature (T₂) = –5° C + 273

Final temperature (T₂) = 268 K

Finally, we shall determine the initial volume of the hydrogen gas. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 268 K

Final volume (V₂) = 212 cm³

Initial volume (V₁) =?

V₁/T₁ = V₂/T₂

V₁ / 323 = 212 / 268

Cross multiply

V₁ × 268 = 323 × 212

V₁ × 268 = 68476

Divide both side by 268

V₁ = 68476 / 268

V₁= 255.51 cm³

Therefore, the initial volume of the hydrogen gas 255.51 cm³

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o