1. Calculate the percent composition of the elements in C4H8O2.

%C = 54.53%

%H = 9.144%

%O = 36.32%

Explanation:

Step 1: Calculate the mass of each element in 1 mole of C₄H₈O₂

We will multiply the number of atoms by the molar mass of the element.

mC: 4 × 12.01 g = 48.04 g

mH: 8 × 1.007 g = 8.056 g

MO: 2 × 16.00 g = 32.00 g

Step 2: Calculate the mass of 1 mole of C₄H₈O₂

We will sum the previously calculated masses of the elements.

mC₄H₈O₂ = mC + mH + mO = 48.04 g + 8.056 g + 32.00 g = 88.10 g

Step 3: Calculate the percent composition of each element

We will use the following expression.

%Element = mElement / mCompound × 100%

%C = 48.04 g / 88.10 g × 100% = 54.53%

%H = 8.056 g / 88.10 g × 100% = 9.144%

%O = 32.00 g / 88.10 g × 100% = 36.32%

2b2t

explanation:

2b2t

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