If 20.0 g NaOH reacts with 30.0 g of H2SO4 how much Na2SO4 is produced? Given: 2NaOH(aq) + H2SO4(aq) | Na2SO4(aq) + 2H2O(l)

10g

Explanation:

find the limiting agent first

using mole ratio

2 moles of NAOH reacts with 2 moles of H2SO4

then 20g of NAOH require 20g of H2SO4

USING mole ratio on the limiting agent and product

2moles of NAOH produces 1 mole of NA2SO4

THEN

20g of NAOH will produce X

THEN solve for X

X =10g

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