In the reaction between ammonia and fluorine shown below 2.643 g of ammonia react with 1.890 g of fluorine. 2NH3(g) + 5F2(g) → N2F4(g) + 6HF(g)

1. The limiting reagent is .
(Convert to grams of N2F4.)
2. if the reaction goes to completion (100% yield), the amount of excess reagent is left over is grams.
3. If the tetrafluorohydrazine (N2F4) is produced in a 75.00% yield, the amount, in grams, that forms is

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the answer is c. nacl

the answer is true. hope it .