Using the reaction, calculate the moles of hydrogen gas produced from the reaction of 4.5 moles of zinc: Zn+2HCl -> ZnCl2+H2

A. 1.0 mols H2
B. 2.0 mols H2
C. 4.0 mols H2
D. 4.5 mols H2

2b2t

explanation:

2b2t

i'm wiling to try and you : )

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally