What is the percent by mass (mv) of a solution with 1.56 g of benzene dissolved in gasoline to make 998.44 mL of solution? (density of gasoline = 0.7489 g/mL) please I need help lol

The percentage by mass of benzene in the solution is approximately 0.2%

Explanation:

The given parameters are;

The mass of the benzene solute dissolved in the gasoline solvent, m₁ = 1.56 g

The total volume of the benzene gasoline solution made, V = 998.44 mL

The density of gasoline, ρ = 0.7489 g/mL

Mass, m = Density, ρ × Volume, V

∴ The mass of gasoline in the 998.44 mL, solution = 0.7489 g/mL × 998.44 mL = 747.731716 g

The total mass of the solution = The mass of the benzene in the solution + The mass of the gasoline in the solution

∴ The total mass of the solution = 747.731716 g + 1.5 g = 749.231716 g

The percentage by mass of benzene in the solution = (1.5 g/749.231716 g)×100 ≈ 0.2% by mass.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)