What is the mass of zinc required to combine with 0.5 mol of chlorine to produce zinc chloride, ZnCI[subscript 2]? [Relative atomic mass : Zn = 65]
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16.25g

Explanation:

Equation for the reaction = Zn + 2Cl = ZnCl2

1 molecule of Zn = 2 molecule of Cl

x mole of Zn = 0.5mol of Cl

mole of Zn = 0.25mol

mass of Zn = 0.25 * 65 = 16.25g

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole