A 2.0 L bag of potato chips in Denver is that 15 C0 print 82 ATM. The same bag is brought to the top of long peaks in the cold winter day. If the back and only spent 2.5 L before exploding and along peak has a temperature of negative 5C and a pressure of 0.45 ATM for the bag explode

hello your question is poorly written below is the complete well written question

.A 2.0 L bag of potato chips in Denver is at 15oC and 0.82 atm. The same bag is brought to the top of Longs Peak on a cold winter day. If the bag can only expand to 2.5 L before exploding and Longs Peak has a temperature of -5oC and a pressure of 0.45atm, will the bag explode? Use the combined gas law to prove this to yourself

answer : The bag will explode

Explanation:

Given data :

Volume of bag ( v1 ) = 2 liters

Initial pressure ( p1 ) = 0.82 atm

Initial temp ( T1 ) = 15 + 273 = 288 k

Final Pressure on long peak (P2) = 0.45 atm

Final temp on Long peak   (T2) = (273 - 5 ) K = 268 K

Determine the Final volume in long peak to know if the bag will explode

applying the gas laws

P1v1 / T1  = P2V2 / T2

V2 = p1*v1*T2 / p2 *T1

V2 = ( 0.82 * 2 * 268 ) / ( 0.45 * 288 )

    = 3.39 Liters

since final volume ( V2 ) > ( v1 )  the bag will explode

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.